2195. Append K Integers With Minimal Sum
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 26% Topics: Array, Math, Greedy, Sorting
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(nlogn)
# Space: O(n)
# greedy
class Solution(object):
def minimalKSum(self, nums, k):
"""
:type nums: List[int]
:type k: int
:rtype: int
"""
result = k*(k+1)//2
curr = k+1
for x in sorted(set(nums)):
if x < curr:
result += curr-x
curr += 1
return result
# Time: O(nlogn)
# Space: O(n)
# greedy
class Solution2(object):
def minimalKSum(self, nums, k):
"""
:type nums: List[int]
:type k: int
:rtype: int
"""
result = prev = 0
nums.append(float("inf"))
for x in sorted(set(nums)):
if not k:
break
cnt = min((x-1)-prev, k)
k -= cnt
result += ((prev+1)+(prev+cnt))*cnt//2
prev = x
return result
Solution from kamyu104/LeetCode-Solutions · MIT