441. Arranging Coins
Read the full problem statement on LeetCode.
Difficulty: easy Acceptance: 47% Topics: Math, Binary Search
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Reference solution (spoiler · python)
# Time: O(logn)
# Space: O(1)
import math
class Solution(object):
def arrangeCoins(self, n):
"""
:type n: int
:rtype: int
"""
return int((math.sqrt(8*n+1)-1) / 2) # sqrt is O(logn) time.
# Time: O(logn)
# Space: O(1)
class Solution2(object):
def arrangeCoins(self, n):
"""
:type n: int
:rtype: int
"""
def check(mid, n):
return mid*(mid+1) <= 2*n
left, right = 1, n
while left <= right:
mid = left + (right-left)//2
if not check(mid, n):
right = mid-1
else:
left = mid+1
return right
Solution from kamyu104/LeetCode-Solutions · MIT