526. Beautiful Arrangement
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 64% Topics: Array, Dynamic Programming, Backtracking, Bit Manipulation, Bitmask
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Reference solution (spoiler · python)
# Time: O(n!)
# Space: O(n)
class Solution(object):
def countArrangement(self, N):
"""
:type N: int
:rtype: int
"""
def countArrangementHelper(n, arr):
if n <= 0:
return 1
count = 0
for i in xrange(n):
if arr[i] % n == 0 or n % arr[i] == 0:
arr[i], arr[n-1] = arr[n-1], arr[i]
count += countArrangementHelper(n - 1, arr)
arr[i], arr[n-1] = arr[n-1], arr[i]
return count
return countArrangementHelper(N, range(1, N+1))
Solution from kamyu104/LeetCode-Solutions · MIT
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