257. Binary Tree Paths
Read the full problem statement on LeetCode.
Difficulty: easy Acceptance: 66% Topics: String, Backtracking, Tree, Depth-First Search, Binary Tree
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(n * h)
# Space: O(h)
class Solution(object):
# @param {TreeNode} root
# @return {string[]}
def binaryTreePaths(self, root):
result, path = [], []
self.binaryTreePathsRecu(root, path, result)
return result
def binaryTreePathsRecu(self, node, path, result):
if node is None:
return
if node.left is node.right is None:
ans = ""
for n in path:
ans += str(n.val) + "->"
result.append(ans + str(node.val))
if node.left:
path.append(node)
self.binaryTreePathsRecu(node.left, path, result)
path.pop()
if node.right:
path.append(node)
self.binaryTreePathsRecu(node.right, path, result)
path.pop()
Solution from kamyu104/LeetCode-Solutions · MIT