LC-0199 Medium LeetCode

199. Binary Tree Right Side View

Tree Depth-First Search Breadth-First Search Binary Tree

Read the full problem statement on LeetCode.

Difficulty: medium Acceptance: 67% Topics: Tree, Depth-First Search, Breadth-First Search, Binary Tree

Reading material

Reference solution (spoiler · python)

# Time:  O(n)
# Space: O(h)

class TreeNode(object):
    def __init__(self, x):
        self.val = x
        self.left = None
        self.right = None


class Solution(object):
    # @param root, a tree node
    # @return a list of integers
    def rightSideView(self, root):
        result = []
        self.rightSideViewDFS(root, 1, result)
        return result

    def rightSideViewDFS(self, node, depth, result):
        if not node:
            return

        if depth > len(result):
            result.append(node.val)

        self.rightSideViewDFS(node.right, depth+1, result)
        self.rightSideViewDFS(node.left, depth+1, result)


# BFS solution
# Time:  O(n)
# Space: O(n)
class Solution2(object):
    # @param root, a tree node
    # @return a list of integers
    def rightSideView(self, root):
        if root is None:
            return []

        result, current = [], [root]
        while current:
            next_level = []
            for node in current:
                if node.left:
                    next_level.append(node.left)
                if node.right:
                    next_level.append(node.right)                
            result.append(node.val)
            current = next_level

        return result

Solution from kamyu104/LeetCode-Solutions · MIT