299. Bulls and Cows
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 51% Topics: Hash Table, String, Counting
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(n)
# Space: O(10) = O(1)
import operator
# One pass solution.
from collections import defaultdict, Counter
from itertools import izip, imap
class Solution(object):
def getHint(self, secret, guess):
"""
:type secret: str
:type guess: str
:rtype: str
"""
A, B = 0, 0
lookup = defaultdict(int)
for s, g in izip(secret, guess):
if s == g:
A += 1
else:
B += int(lookup[s] < 0) + int(lookup[g] > 0)
lookup[s] += 1
lookup[g] -= 1
return "%dA%dB" % (A, B)
# Two pass solution.
class Solution2(object):
def getHint(self, secret, guess):
"""
:type secret: str
:type guess: str
:rtype: str
"""
A = sum(imap(operator.eq, secret, guess))
B = sum((Counter(secret) & Counter(guess)).values()) - A
return "%dA%dB" % (A, B)
Solution from kamyu104/LeetCode-Solutions · MIT
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