77. Combinations
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 73% Topics: Backtracking
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Reference solution (spoiler · python)
# Time: O(k * C(n, k))
# Space: O(k)
class Solution(object):
def combine(self, n, k):
"""
:type n: int
:type k: int
:rtype: List[List[int]]
"""
if k > n:
return []
nums, idxs = range(1, n+1), range(k)
result = [[nums[i] for i in idxs]]
while True:
for i in reversed(xrange(k)):
if idxs[i] != i+n-k:
break
else:
break
idxs[i] += 1
for j in xrange(i+1, k):
idxs[j] = idxs[j-1]+1
result.append([nums[i] for i in idxs])
return result
# Time: O(k * C(n, k))
# Space: O(k)
class Solution2(object):
def combine(self, n, k):
"""
:type n: int
:type k: int
:rtype: List[List[int]]
"""
result, combination = [], []
i = 1
while True:
if len(combination) == k:
result.append(combination[:])
if len(combination) == k or \
len(combination)+(n-i+1) < k:
if not combination:
break
i = combination.pop()+1
else:
combination.append(i)
i += 1
return result
# Time: O(k * C(n, k))
# Space: O(k)
class Solution3(object):
def combine(self, n, k):
"""
:type n: int
:type k: int
:rtype: List[List[int]]
"""
def combineDFS(n, start, intermediate, k, result):
if k == 0:
result.append(intermediate[:])
return
for i in xrange(start, n):
intermediate.append(i+1)
combineDFS(n, i+1, intermediate, k-1, result)
intermediate.pop()
result = []
combineDFS(n, 0, [], k, result)
return result
Solution from kamyu104/LeetCode-Solutions · MIT
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