1008. Construct Binary Search Tree from Preorder Traversal
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 83% Topics: Array, Stack, Tree, Binary Search Tree, Monotonic Stack, Binary Tree
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Reference solution (spoiler · python)
# Time: O(n)
# Space: O(h)
# Definition for a binary tree node.
class TreeNode(object):
def __init__(self, x):
self.val = x
self.left = None
self.right = None
class Solution(object):
def bstFromPreorder(self, preorder):
"""
:type preorder: List[int]
:rtype: TreeNode
"""
def bstFromPreorderHelper(preorder, left, right, index):
if index[0] == len(preorder) or \
preorder[index[0]] < left or \
preorder[index[0]] > right:
return None
root = TreeNode(preorder[index[0]])
index[0] += 1
root.left = bstFromPreorderHelper(preorder, left, root.val, index)
root.right = bstFromPreorderHelper(preorder, root.val, right, index)
return root
return bstFromPreorderHelper(preorder, float("-inf"), float("inf"), [0])
Solution from kamyu104/LeetCode-Solutions · MIT