2947. Count Beautiful Substrings I
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 59% Topics: Hash Table, Math, String, Enumeration, Number Theory, Prefix Sum
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Reference solution (spoiler · python)
# Time: O(n + sqrt(k))
# Space: O(n)
# number theory, prefix sum, freq table
class Solution(object):
def beautifulSubstrings(self, s, k):
"""
:type s: str
:type k: int
:rtype: int
"""
VOWELS = set("aeiou")
prefix = [0]*(len(s)+1)
for i in xrange(len(s)):
prefix[i+1] = prefix[i]+(+1 if s[i] in VOWELS else -1)
new_k = 1
x = k
for i in xrange(2, k+1):
if i*i > k:
break
cnt = 0
while x%i == 0:
x //= i
cnt += 1
if cnt:
new_k *= i**((cnt+1)//2+int(i == 2))
if x != 1:
new_k *= x**((1+1)//2+int(x == 2))
cnt = collections.Counter()
result = 0
for i, p in enumerate(prefix):
result += cnt[p, i%new_k]
cnt[p, i%new_k] += 1
return result
# Time: O(n^2)
# Space: O(1)
# brute force
class Solution2(object):
def beautifulSubstrings(self, s, k):
"""
:type s: str
:type k: int
:rtype: int
"""
VOWELS = set("aeiou")
result = 0
for i in xrange(len(s)):
c = v = 0
for j in xrange(i, len(s)):
if s[j] in VOWELS:
v += 1
else:
c += 1
if c == v and (c*v)%k == 0:
result += 1
return result
Solution from kamyu104/LeetCode-Solutions · MIT