2364. Count Number of Bad Pairs
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 54% Topics: Array, Hash Table, Math, Counting
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Reference solution (spoiler · python)
# Time: O(n)
# Space: O(n)
import collections
# freq table
class Solution(object):
def countBadPairs(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
result = len(nums)*(len(nums)-1)//2
cnt = collections.Counter()
for i, x in enumerate(nums):
result -= cnt[x-i]
cnt[x-i] += 1
return result
Solution from kamyu104/LeetCode-Solutions · MIT