2250. Count Number of Rectangles Containing Each Point
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Difficulty: medium Acceptance: 36% Topics: Array, Hash Table, Binary Search, Binary Indexed Tree, Sorting
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Reference solution (spoiler · python)
# Time: O(nlogn + m * max_y * logn), n = len(rectangles), m = len(points)
# Space: O(n)
import bisect
# bucket sort, binary search
class Solution(object):
def countRectangles(self, rectangles, points):
"""
:type rectangles: List[List[int]]
:type points: List[List[int]]
:rtype: List[int]
"""
max_y = max(y for _, y in rectangles)
buckets = [[] for _ in xrange(max_y+1)]
for x, y in rectangles:
buckets[y].append(x)
for bucket in buckets:
bucket.sort()
return [sum(len(buckets[y])-bisect.bisect_left(buckets[y], x) for y in xrange(y, max_y+1))
for x, y in points]
Solution from kamyu104/LeetCode-Solutions · MIT
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