641. Design Circular Deque
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 64% Topics: Array, Linked List, Design, Queue
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Reference solution (spoiler · python)
# Time: O(1)
# Space: O(k)
class MyCircularDeque(object):
def __init__(self, k):
"""
Initialize your data structure here. Set the size of the deque to be k.
:type k: int
"""
self.__start = 0
self.__size = 0
self.__buffer = [0] * k
def insertFront(self, value):
"""
Adds an item at the front of Deque. Return true if the operation is successful.
:type value: int
:rtype: bool
"""
if self.isFull():
return False
self.__start = (self.__start-1) % len(self.__buffer)
self.__buffer[self.__start] = value
self.__size += 1
return True
def insertLast(self, value):
"""
Adds an item at the rear of Deque. Return true if the operation is successful.
:type value: int
:rtype: bool
"""
if self.isFull():
return False
self.__buffer[(self.__start+self.__size) % len(self.__buffer)] = value
self.__size += 1
return True
def deleteFront(self):
"""
Deletes an item from the front of Deque. Return true if the operation is successful.
:rtype: bool
"""
if self.isEmpty():
return False
self.__start = (self.__start+1) % len(self.__buffer)
self.__size -= 1
return True
def deleteLast(self):
"""
Deletes an item from the rear of Deque. Return true if the operation is successful.
:rtype: bool
"""
if self.isEmpty():
return False
self.__size -= 1
return True
def getFront(self):
"""
Get the front item from the deque.
:rtype: int
"""
return -1 if self.isEmpty() else self.__buffer[self.__start]
def getRear(self):
"""
Get the last item from the deque.
:rtype: int
"""
return -1 if self.isEmpty() else self.__buffer[(self.__start+self.__size-1) % len(self.__buffer)]
def isEmpty(self):
"""
Checks whether the circular deque is empty or not.
:rtype: bool
"""
return self.__size == 0
def isFull(self):
"""
Checks whether the circular deque is full or not.
:rtype: bool
"""
return self.__size == len(self.__buffer)
Solution from kamyu104/LeetCode-Solutions · MIT
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