1103. Distribute Candies to People
Read the full problem statement on LeetCode.
Difficulty: easy Acceptance: 66% Topics: Math, Simulation
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Reference solution (spoiler · python)
# Time: O(n + logc), c is the number of candies
# Space: O(1)
class Solution(object):
def distributeCandies(self, candies, num_people):
"""
:type candies: int
:type num_people: int
:rtype: List[int]
"""
# find max integer p s.t. sum(1 + 2 + ... + p) <= C
# => remaining : 0 <= C-(1+p)*p/2 < p+1
# => -2p-2 < p^2+p-2C <= 0
# => 2C+1/4 < (p+3/2)^2 and (p+1/2)^2 <= 2C+1/4
# => sqrt(2C+1/4)-3/2 < p <= sqrt(2C+1/4)-1/2
# => p = floor(sqrt(2C+1/4)-1/2)
p = int((2*candies + 0.25)**0.5 - 0.5)
remaining = candies - (p+1)*p//2
rows, cols = divmod(p, num_people)
result = [0]*num_people
for i in xrange(num_people):
result[i] = (i+1)*(rows+1) + (rows*(rows+1)//2)*num_people if i < cols else \
(i+1)*rows + ((rows-1)*rows//2)*num_people
result[cols] += remaining
return result
# Time: O(n + logc), c is the number of candies
# Space: O(1)
class Solution2(object):
def distributeCandies(self, candies, num_people):
"""
:type candies: int
:type num_people: int
:rtype: List[int]
"""
# find max integer p s.t. sum(1 + 2 + ... + p) <= C
left, right = 1, candies
while left <= right:
mid = left + (right-left)//2
if not ((mid <= candies*2 // (mid+1))):
right = mid-1
else:
left = mid+1
p = right
remaining = candies - (p+1)*p//2
rows, cols = divmod(p, num_people)
result = [0]*num_people
for i in xrange(num_people):
result[i] = (i+1)*(rows+1) + (rows*(rows+1)//2)*num_people if i < cols else \
(i+1)*rows + ((rows-1)*rows//2)*num_people
result[cols] += remaining
return result
# Time: O(sqrt(c)), c is the number of candies
# Space: O(1)
class Solution3(object):
def distributeCandies(self, candies, num_people):
"""
:type candies: int
:type num_people: int
:rtype: List[int]
"""
result = [0]*num_people
i = 0
while candies != 0:
result[i % num_people] += min(candies, i+1)
candies -= min(candies, i+1)
i += 1
return result
Solution from kamyu104/LeetCode-Solutions · MIT
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