855. Exam Room
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 43% Topics: Design, Heap (Priority Queue), Ordered Set
View full problem on LeetCode Reference solution (spoiler · python)
# Time: seat: O(logn), amortized
# leave: O(logn)
# Space: O(n)
import heapq
class ExamRoom(object):
def __init__(self, N):
"""
:type N: int
"""
self.__num = N
self.__seats = {-1: [-1, self.__num], self.__num: [-1, self.__num]}
self.__max_heap = [(-self.__distance((-1, self.__num)), -1, self.__num)]
def seat(self):
"""
:rtype: int
"""
while self.__max_heap[0][1] not in self.__seats or \
self.__max_heap[0][2] not in self.__seats or \
self.__seats[self.__max_heap[0][1]][1] != self.__max_heap[0][2] or \
self.__seats[self.__max_heap[0][2]][0] != self.__max_heap[0][1]:
heapq.heappop(self.__max_heap) # lazy deletion
_, left, right = heapq.heappop(self.__max_heap)
mid = 0 if left == -1 \
else self.__num-1 if right == self.__num \
else (left+right) // 2
self.__seats[mid] = [left, right]
heapq.heappush(self.__max_heap, (-self.__distance((left, mid)), left, mid))
heapq.heappush(self.__max_heap, (-self.__distance((mid, right)), mid, right))
self.__seats[left][1] = mid
self.__seats[right][0] = mid
return mid
def leave(self, p):
"""
:type p: int
:rtype: void
"""
left, right = self.__seats[p]
self.__seats.pop(p)
self.__seats[left][1] = right
self.__seats[right][0] = left
heapq.heappush(self.__max_heap, (-self.__distance((left, right)), left, right))
def __distance(self, segment):
return segment[1]-segment[0]-1 if segment[0] == -1 or segment[1] == self.__num \
else (segment[1]-segment[0]) // 2
Solution from kamyu104/LeetCode-Solutions · MIT
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