34. Find First and Last Position of Element in Sorted Array
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 47% Topics: Array, Binary Search
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(logn)
# Space: O(1)
class Solution(object):
def searchRange(self, nums, target):
"""
:type nums: List[int]
:type target: int
:rtype: List[int]
"""
def binarySearch(n, check): # usually use
left, right = 0, n-1 # search in [0, n-1], return n if not found
while left <= right:
mid = left + (right-left)//2
if check(mid):
right = mid-1
else:
left = mid+1
return left # or return right+1
def binarySearch2(n, check): # frequently use
left, right = 0, n # search in [0, n), return n if not found
while left < right:
mid = left + (right-left)//2
if check(mid):
right = mid
else:
left = mid+1
return left # or return right
def binarySearch3(n, check): # never use
left, right = -1, n-1 # search in (-1, n-1], return n if not found
while left < right:
mid = right - (right-left)//2
if check(mid):
right = mid-1
else:
left = mid
return left+1 # or return right+1
def binarySearch4(n, check): # sometimes use
left, right = -1, n # search in (-1, n), return n if not found
while right-left >= 2:
mid = left + (right-left)//2
if check(mid):
right = mid
else:
left = mid
return left+1 # or return right
# Find the first idx where nums[idx] >= target
left = binarySearch(len(nums), lambda i: nums[i] >= target)
if left == len(nums) or nums[left] != target:
return [-1, -1]
# Find the first idx where nums[idx] > target
right = binarySearch(len(nums), lambda i: nums[i] > target)
return [left, right-1]
Solution from kamyu104/LeetCode-Solutions · MIT