2099. Find Subsequence of Length K With the Largest Sum
Read the full problem statement on LeetCode.
Difficulty: easy Acceptance: 45% Topics: Array, Hash Table, Sorting, Heap (Priority Queue)
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(n)
# Space: O(n)
import random
# quick select solution
class Solution(object):
def maxSubsequence(self, nums, k):
"""
:type nums: List[int]
:type k: int
:rtype: List[int]
"""
def nth_element(nums, n, compare=lambda a, b: a < b):
def tri_partition(nums, left, right, target, compare):
mid = left
while mid <= right:
if nums[mid] == target:
mid += 1
elif compare(nums[mid], target):
nums[left], nums[mid] = nums[mid], nums[left]
left += 1
mid += 1
else:
nums[mid], nums[right] = nums[right], nums[mid]
right -= 1
return left, right
left, right = 0, len(nums)-1
while left <= right:
pivot_idx = random.randint(left, right)
pivot_left, pivot_right = tri_partition(nums, left, right, nums[pivot_idx], compare)
if pivot_left <= n <= pivot_right:
return
elif pivot_left > n:
right = pivot_left-1
else: # pivot_right < n.
left = pivot_right+1
partition = nums[:]
nth_element(partition, k-1, compare=lambda a, b: a > b)
cnt = sum(partition[i] == partition[k-1] for i in xrange(k))
result = []
for x in nums:
if x > partition[k-1]:
result.append(x)
elif x == partition[k-1] and cnt > 0:
cnt -= 1
result.append(x)
return result
Solution from kamyu104/LeetCode-Solutions · MIT