1195. Fizz Buzz Multithreaded
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 74% Topics: Concurrency
View full problem on LeetCode Reference solution (spoiler · python)
# Time: O(n)
# Space: O(1)
import threading
class FizzBuzz(object):
def __init__(self, n):
self.__n = n
self.__curr = 0
self.__cv = threading.Condition()
# printFizz() outputs "fizz"
def fizz(self, printFizz):
"""
:type printFizz: method
:rtype: void
"""
for i in xrange(1, self.__n+1):
with self.__cv:
while self.__curr % 4 != 0:
self.__cv.wait()
self.__curr += 1
if i % 3 == 0 and i % 5 != 0:
printFizz()
self.__cv.notify_all()
# printBuzz() outputs "buzz"
def buzz(self, printBuzz):
"""
:type printBuzz: method
:rtype: void
"""
for i in xrange(1, self.__n+1):
with self.__cv:
while self.__curr % 4 != 1:
self.__cv.wait()
self.__curr += 1
if i % 3 != 0 and i % 5 == 0:
printBuzz()
self.__cv.notify_all()
# printFizzBuzz() outputs "fizzbuzz"
def fizzbuzz(self, printFizzBuzz):
"""
:type printFizzBuzz: method
:rtype: void
"""
for i in xrange(1, self.__n+1):
with self.__cv:
while self.__curr % 4 != 2:
self.__cv.wait()
self.__curr += 1
if i % 3 == 0 and i % 5 == 0:
printFizzBuzz()
self.__cv.notify_all()
# printNumber(x) outputs "x", where x is an integer.
def number(self, printNumber):
"""
:type printNumber: method
:rtype: void
"""
for i in xrange(1, self.__n+1):
with self.__cv:
while self.__curr % 4 != 3:
self.__cv.wait()
self.__curr += 1
if i % 3 != 0 and i % 5 != 0:
printNumber(i)
self.__cv.notify_all()
Solution from kamyu104/LeetCode-Solutions · MIT
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