3435. Frequencies of Shortest Supersequences
Read the full problem statement on LeetCode.
Difficulty: hard Acceptance: 15% Topics: Array, String, Bit Manipulation, Graph, Topological Sort, Enumeration
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(n + k^2 * 2^k), k = len(indegree) <= 16
# Space: O(k^2)
import collections
# bitmasks, topological sort
class Solution(object):
def supersequences(self, words):
"""
:type words: List[str]
:rtype: List[List[int]]
"""
def f(x):
x = ord(x)-ord('a')
if char_to_int[x] == -1:
int_to_char[len(indegree)] = x
char_to_int[x] = len(indegree)
indegree.append(0)
return char_to_int[x]
def topological_sort(cnt):
total = sum(cnt)
if total > ans[0]:
return
new_cnt = cnt[:]
new_indgree = indegree[:]
lookup = [False]*len(cnt)
q = []
for u in xrange(len(indegree)):
if not new_indgree[u] or new_cnt[u] == 2:
new_cnt[u] -= 1
lookup[u] = True
q.append(u)
while q:
new_q = []
for u in q:
for v in adj[u]:
new_indgree[v] -= 1
if new_indgree[v]:
continue
new_cnt[v] -= 1
if lookup[v]:
continue
lookup[v] = True
new_q.append(v)
q = new_q
if any(new_cnt):
return
if total < ans[0]:
ans[0] = total
ans[1][:] = []
ans[1].append(cnt)
adj = [[] for _ in xrange(26)]
char_to_int, int_to_char, indegree = [-1]*26, [0]*26, []
for w in words:
adj[f(w[0])].append(f(w[1]))
indegree[f(w[1])] += 1
ans = [float("inf"), []]
for mask in xrange(1<<len(indegree)):
topological_sort([2 if mask&(1<<i) else 1 for i in xrange(len(indegree))])
result = []
for cnt in ans[1]:
new_cnt = [0]*26
for i, x in enumerate(cnt):
new_cnt[int_to_char[i]] = x
result.append(new_cnt)
return result
Solution from kamyu104/LeetCode-Solutions · MIT