274. H-Index
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Difficulty: medium Acceptance: 40% Topics: Array, Sorting, Counting Sort
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Reference solution (spoiler · python)
# Time: O(n)
# Space: O(n)
class Solution(object):
def hIndex(self, citations):
"""
:type citations: List[int]
:rtype: int
"""
n = len(citations)
count = [0] * (n + 1)
for x in citations:
# Put all x >= n in the same bucket.
if x >= n:
count[n] += 1
else:
count[x] += 1
h = 0
for i in reversed(xrange(0, n + 1)):
h += count[i]
if h >= i:
return i
return h
# Time: O(nlogn)
# Space: O(1)
class Solution2(object):
def hIndex(self, citations):
"""
:type citations: List[int]
:rtype: int
"""
citations.sort(reverse=True)
h = 0
for x in citations:
if x >= h + 1:
h += 1
else:
break
return h
# Time: O(nlogn)
# Space: O(n)
class Solution3(object):
def hIndex(self, citations):
"""
:type citations: List[int]
:rtype: int
"""
return sum(x >= i + 1 for i, x in enumerate(sorted(citations, reverse=True)))
Solution from kamyu104/LeetCode-Solutions · MIT
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