676. Implement Magic Dictionary

# Time:  O(n), n is the length of the word
# Space: O(d)

import collections


class MagicDictionary(object):

    def __init__(self):
        """
        Initialize your data structure here.
        """
        _trie = lambda: collections.defaultdict(_trie)
        self.trie = _trie()


    def buildDict(self, dictionary):
        """
        Build a dictionary through a list of words
        :type dictionary: List[str]
        :rtype: void
        """
        for word in dictionary:
            reduce(dict.__getitem__, word, self.trie).setdefault("_end")


    def search(self, word):
        """
        Returns if there is any word in the trie that equals to the given word after modifying exactly one character
        :type word: str
        :rtype: bool
        """
        def find(word, curr, i, mistakeAllowed):
            if i == len(word):
                return "_end" in curr and not mistakeAllowed

            if word[i] not in curr:
                return any(find(word, curr[c], i+1, False) for c in curr if c != "_end") \
                           if mistakeAllowed else False

            if mistakeAllowed:
                return find(word, curr[word[i]], i+1, True) or \
                       any(find(word, curr[c], i+1, False) \
                           for c in curr if c not in ("_end", word[i]))
            return find(word, curr[word[i]], i+1, False)

        return find(word, self.trie, 0, True)

Solution from kamyu104/LeetCode-Solutions · MIT