2248. Intersection of Multiple Arrays

# Time:  O(n * l + r), n = len(nums), l = len(nums[0])
# Space: O(r), r = max(nums)-min(nums)

# freq table, counting sort
class Solution(object):
    def intersection(self, nums):
        """
        :type nums: List[List[int]]
        :rtype: List[int]
        """
        MAX_NUM = 1000
        cnt = [0]*(MAX_NUM+1)
        for num in nums:
            for x in num:
                cnt[x] += 1
        return [i for i in xrange(1, MAX_NUM+1) if cnt[i] == len(nums)]


# Time:  O(n * l + r), n = len(nums), l = len(nums[0]), r = max(nums)-min(nums)
# Space: O(l)
# hash table, counting sort
class Solution2(object):
    def intersection(self, nums):
        """
        :type nums: List[List[int]]
        :rtype: List[int]
        """
        result = set(nums[0])
        for i in xrange(1, len(nums)):
            result = set(x for x in nums[i] if x in result)
        return [i for i in xrange(min(result), max(result)+1) if i in result] if result else []


# Time:  O(n * l + llogl), n = len(nums), l = len(nums[0])
# Space: O(l)
# hash table, sort
class Solution3(object):
    def intersection(self, nums):
        """
        :type nums: List[List[int]]
        :rtype: List[int]
        """
        result = set(nums[0])
        for i in xrange(1, len(nums)):
            result = set(x for x in nums[i] if x in result)
        return sorted(result)

Solution from kamyu104/LeetCode-Solutions · MIT