392. Is Subsequence
Read the full problem statement on LeetCode.
Difficulty: easy Acceptance: 48% Topics: Two Pointers, String, Dynamic Programming
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(n)
# Space: O(1)
class Solution(object):
def isSubsequence(self, s, t):
"""
:type s: str
:type t: str
:rtype: bool
"""
if not s:
return True
i = 0
for c in t:
if c == s[i]:
i += 1
if i == len(s):
break
return i == len(s)
Solution from kamyu104/LeetCode-Solutions · MIT