1340. Jump Game V
Read the full problem statement on LeetCode.
Difficulty: hard Acceptance: 64% Topics: Array, Dynamic Programming, Sorting
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(n)
# Space: O(n)
import collections
import itertools
# sliding window + top-down dp
class Solution(object):
def maxJumps(self, arr, d):
"""
:type arr: List[int]
:type d: int
:rtype: int
"""
def dp(arr, d, i, left, right, lookup):
if lookup[i]:
return lookup[i]
lookup[i] = 1
for j in itertools.chain(left[i], right[i]):
# each dp[j] will be visited at most twice
lookup[i] = max(lookup[i], dp(arr, d, j, left, right, lookup)+1)
return lookup[i]
left, decreasing_dq = [[] for _ in xrange(len(arr))], collections.deque()
for i in xrange(len(arr)):
if decreasing_dq and i - decreasing_dq[0] == d+1:
decreasing_dq.popleft()
while decreasing_dq and arr[decreasing_dq[-1]] < arr[i]:
if left[i] and arr[left[i][-1]] != arr[decreasing_dq[-1]]:
left[i] = []
left[i].append(decreasing_dq.pop())
decreasing_dq.append(i)
right, decreasing_dq = [[] for _ in xrange(len(arr))], collections.deque()
for i in reversed(xrange(len(arr))):
if decreasing_dq and decreasing_dq[0] - i == d+1:
decreasing_dq.popleft()
while decreasing_dq and arr[decreasing_dq[-1]] < arr[i]:
if right[i] and arr[right[i][-1]] != arr[decreasing_dq[-1]]:
right[i] = []
right[i].append(decreasing_dq.pop())
decreasing_dq.append(i)
lookup = [0]*len(arr)
return max(itertools.imap(lambda x: dp(arr, d, x, left, right, lookup), xrange(len(arr))))
# Time: O(nlogn)
# Space: O(n)
# mono stack + bottom-up dp
class Solution2(object):
def maxJumps(self, arr, d):
"""
:type arr: List[int]
:type d: int
:rtype: int
"""
left, decreasing_stk = [[] for _ in xrange(len(arr))], []
for i in xrange(len(arr)):
while decreasing_stk and arr[decreasing_stk[-1]] < arr[i]:
if i - decreasing_stk[-1] <= d:
if left[i] and arr[left[i][-1]] != arr[decreasing_stk[-1]]:
left[i] = []
left[i].append(decreasing_stk[-1])
decreasing_stk.pop()
decreasing_stk.append(i)
right, decreasing_stk = [[] for _ in xrange(len(arr))], []
for i in reversed(xrange(len(arr))):
while decreasing_stk and arr[decreasing_stk[-1]] < arr[i]:
if decreasing_stk[-1] - i <= d:
if right[i] and arr[right[i][-1]] != arr[decreasing_stk[-1]]:
right[i] = []
right[i].append(decreasing_stk[-1])
decreasing_stk.pop()
decreasing_stk.append(i)
dp = [0]*len(arr)
for a, i in sorted([a, i] for i, a in enumerate(arr)):
dp[i] = 1
for j in itertools.chain(left[i], right[i]):
# each dp[j] will be visited at most twice
dp[i] = max(dp[i], dp[j]+1)
return max(dp)
# Template:
# https://github.com/kamyu104/FacebookHackerCup-2018/blob/master/Final%20Round/the_claw.py
class SegmentTree(object):
def __init__(self, N,
build_fn=lambda x, y: [y]*(2*x),
query_fn=max,
update_fn=lambda x, y: y,
default_val=0):
self.N = N
self.H = (N-1).bit_length()
self.query_fn = query_fn
self.update_fn = update_fn
self.default_val = default_val
self.tree = build_fn(N, default_val)
self.lazy = [None]*N
def __apply(self, x, val):
self.tree[x] = self.update_fn(self.tree[x], val)
if x < self.N:
self.lazy[x] = self.update_fn(self.lazy[x], val)
def update(self, L, R, h): # Time: O(logN), Space: O(N)
def pull(x):
while x > 1:
x //= 2
self.tree[x] = self.query_fn(self.tree[x*2], self.tree[x*2+1])
if self.lazy[x] is not None:
self.tree[x] = self.update_fn(self.tree[x], self.lazy[x])
L += self.N
R += self.N
L0, R0 = L, R
while L <= R:
if L & 1: # is right child
self.__apply(L, h)
L += 1
if R & 1 == 0: # is left child
self.__apply(R, h)
R -= 1
L //= 2
R //= 2
pull(L0)
pull(R0)
def query(self, L, R): # Time: O(logN), Space: O(N)
def push(x):
n = 2**self.H
while n != 1:
y = x // n
if self.lazy[y] is not None:
self.__apply(y*2, self.lazy[y])
self.__apply(y*2 + 1, self.lazy[y])
self.lazy[y] = None
n //= 2
result = self.default_val
if L > R:
return result
L += self.N
R += self.N
push(L)
push(R)
while L <= R:
if L & 1: # is right child
result = self.query_fn(result, self.tree[L])
L += 1
if R & 1 == 0: # is left child
result = self.query_fn(result, self.tree[R])
R -= 1
L //= 2
R //= 2
return result
def __str__(self):
showList = []
for i in xrange(self.N):
showList.append(self.query(i, i))
return ",".join(map(str, showList))
# Time: O(nlogn)
# Space: O(n)
# mono stack + bottom-up dp + segment tree
class Solution3(object):
def maxJumps(self, arr, d):
"""
:type arr: List[int]
:type d: int
:rtype: int
"""
left, decreasing_stk = range(len(arr)), []
for i in xrange(len(arr)):
while decreasing_stk and arr[decreasing_stk[-1]] < arr[i]:
if i - decreasing_stk[-1] <= d:
left[i] = decreasing_stk[-1]
decreasing_stk.pop()
decreasing_stk.append(i)
right, decreasing_stk = range(len(arr)), []
for i in reversed(xrange(len(arr))):
while decreasing_stk and arr[decreasing_stk[-1]] < arr[i]:
if decreasing_stk[-1] - i <= d:
right[i] = decreasing_stk[-1]
decreasing_stk.pop()
decreasing_stk.append(i)
segment_tree = SegmentTree(len(arr))
for _, i in sorted([x, i] for i, x in enumerate(arr)):
segment_tree.update(i, i, segment_tree.query(left[i], right[i]) + 1)
return segment_tree.query(0, len(arr)-1)
Solution from kamyu104/LeetCode-Solutions · MIT
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