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LC-0460 Hard LeetCode

460. LFU Cache

Read the full problem statement on LeetCode.
Difficulty: hard Acceptance: 46% Topics: Hash Table, Linked List, Design, Doubly-Linked List
View full problem on LeetCode
Reference solution (spoiler · python)
# Time:  O(1), per operation
# Space: O(k), k is the capacity of cache

import collections


# using OrderedDict
class LFUCache(object):

    def __init__(self, capacity):
        """
        :type capacity: int
        """
        self.__capa = capacity
        self.__size = 0
        self.__min_freq = float("inf")
        self.__freq_to_nodes = collections.defaultdict(collections.OrderedDict)
        self.__key_to_freq = {}

    def get(self, key):
        """
        :type key: int
        :rtype: int
        """
        if key not in self.__key_to_freq:
            return -1
        value = self.__freq_to_nodes[self.__key_to_freq[key]][key]
        self.__update(key, value)
        return value

    def put(self, key, value):
        """
        :type key: int
        :type value: int
        :rtype: void
        """
        if self.__capa <= 0:
            return

        if key not in self.__key_to_freq and self.__size == self.__capa:
            del self.__key_to_freq[self.__freq_to_nodes[self.__min_freq].popitem(last=False)[0]]
            if not self.__freq_to_nodes[self.__min_freq]:
                del self.__freq_to_nodes[self.__min_freq]
            self.__size -= 1
        self.__update(key, value)
        
    def __update(self, key, value):
        freq = 0
        if key in self.__key_to_freq:
            freq = self.__key_to_freq[key]
            del self.__freq_to_nodes[freq][key]
            if not self.__freq_to_nodes[freq]:
                del self.__freq_to_nodes[freq]
                if self.__min_freq == freq:
                    self.__min_freq += 1
            self.__size -= 1

        freq += 1
        self.__min_freq = min(self.__min_freq, freq)
        self.__key_to_freq[key] = freq
        self.__freq_to_nodes[freq][key] = value
        self.__size += 1


# Time:  O(1), per operation
# Space: O(k), k is the capacity of cache
import collections


class ListNode(object):
    def __init__(self, key, value, freq):
        self.key = key
        self.val = value
        self.freq = freq
        self.next = None
        self.prev = None


class LinkedList(object):
    def __init__(self):
        self.head = None
        self.tail = None

    def append(self, node):
        node.next, node.prev = None, None  # avoid dirty node
        if self.head is None:
            self.head = node
        else:
            self.tail.next = node
            node.prev = self.tail
        self.tail = node

    def delete(self, node):
        if node.prev:
            node.prev.next = node.next
        else:
            self.head = node.next
        if node.next:
            node.next.prev = node.prev
        else:
            self.tail = node.prev
        node.next, node.prev = None, None  # make node clean


class LFUCache2(object):

    def __init__(self, capacity):
        """
        :type capacity: int
        """
        self.__capa = capacity
        self.__size = 0
        self.__min_freq = float("inf")
        self.__freq_to_nodes = collections.defaultdict(LinkedList)
        self.__key_to_node = {}

    def get(self, key):
        """
        :type key: int
        :rtype: int
        """
        if key not in self.__key_to_node:
            return -1
        value = self.__key_to_node[key].val
        self.__update(key, value)
        return value

    def put(self, key, value):
        """
        :type key: int
        :type value: int
        :rtype: void
        """
        if self.__capa <= 0:
            return

        if key not in self.__key_to_node and self.__size == self.__capa:
            del self.__key_to_node[self.__freq_to_nodes[self.__min_freq].head.key]
            self.__freq_to_nodes[self.__min_freq].delete(self.__freq_to_nodes[self.__min_freq].head)
            if not self.__freq_to_nodes[self.__min_freq].head:
                del self.__freq_to_nodes[self.__min_freq]
            self.__size -= 1
        self.__update(key, value)
        
    def __update(self, key, value):
        freq = 0
        if key in self.__key_to_node:
            old_node = self.__key_to_node[key]
            freq = old_node.freq
            self.__freq_to_nodes[freq].delete(old_node)
            if not self.__freq_to_nodes[freq].head:
                del self.__freq_to_nodes[freq]
                if self.__min_freq == freq:
                    self.__min_freq += 1
            self.__size -= 1

        freq += 1
        self.__min_freq = min(self.__min_freq, freq)
        self.__key_to_node[key] = ListNode(key, value, freq)
        self.__freq_to_nodes[freq].append(self.__key_to_node[key])
        self.__size += 1

Solution from kamyu104/LeetCode-Solutions · MIT