2765. Longest Alternating Subarray
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Difficulty: easy Acceptance: 34% Topics: Array, Enumeration
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Reference solution (spoiler · python)
# Time: O(n)
# Space: O(1)
# array
class Solution(object):
def alternatingSubarray(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
result = l = -1
for i in xrange(len(nums)-1):
if l != -1 and nums[i-1] == nums[i+1]:
l += 1
else:
l = 2 if nums[i+1]-nums[i] == 1 else -1
result = max(result, l)
return result
Solution from kamyu104/LeetCode-Solutions · MIT
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