3093. Longest Common Suffix Queries
Read the full problem statement on LeetCode.
Difficulty: hard Acceptance: 37% Topics: Array, String, Trie
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O((n + q) * l)
# Space: O(t)
# trie
class Solution(object):
def stringIndices(self, wordsContainer, wordsQuery):
"""
:type wordsContainer: List[str]
:type wordsQuery: List[str]
:rtype: List[int]
"""
INF = float("INF")
class Trie(object):
def __init__(self):
self.__nodes = []
self.__mns = []
self.__new_node()
def __new_node(self):
self.__nodes.append([-1]*26)
self.__mns.append((INF, INF))
return len(self.__nodes)-1
def add(self, i, w):
curr = 0
self.__mns[curr] = min(self.__mns[curr], (len(w), i))
for c in reversed(w):
x = ord(c)-ord('a')
if self.__nodes[curr][x] == -1:
self.__nodes[curr][x] = self.__new_node()
curr = self.__nodes[curr][x]
self.__mns[curr] = min(self.__mns[curr], (len(w), i))
def query(self, w):
curr = 0
for c in reversed(w):
x = ord(c)-ord('a')
if self.__nodes[curr][x] == -1:
break
curr = self.__nodes[curr][x]
return self.__mns[curr][1]
trie = Trie()
for i, w in enumerate(wordsContainer):
trie.add(i, w)
return [trie.query(w) for w in wordsQuery]
Solution from kamyu104/LeetCode-Solutions · MIT