3372. Maximize the Number of Target Nodes After Connecting Trees I
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Difficulty: medium Acceptance: 48% Topics: Tree, Depth-First Search, Breadth-First Search
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Reference solution (spoiler · python)
# Time: O(nlogn + mlogm)
# Space: O(n + m)
# dfs, centroid decomposition, prefix sum
class Solution(object):
def maxTargetNodes(self, edges1, edges2, k):
"""
:type edges1: List[List[int]]
:type edges2: List[List[int]]
:type k: int
:rtype: List[int]
"""
def centroid_decomposition(adj, k):
def dfs(u):
# https://usaco.guide/plat/centroid
def find_subtree_size(u, p):
sizes[u] = 1
for v in adj[u]:
if v == p or lookup[v]:
continue
sizes[u] += find_subtree_size(v, u)
return sizes[u]
def find_centroid(u, p):
for v in adj[u]:
if v == p or lookup[v]:
continue
if sizes[v]*2 > n:
return find_centroid(v, u)
return u
def count(u, p, d):
if d > k:
return
if d-1 == len(cnt):
cnt.append(0)
cnt[d-1] += 1
for v in adj[u]:
if v == p or lookup[v]:
continue
count(v, u, d+1)
def update(u, p, d):
if d > k:
return
result[u] += total[min(k-d, len(total)-1)]-curr[min(k-d, len(curr)-1)]
for v in adj[u]:
if v == p or lookup[v]:
continue
update(v, u, d+1)
find_subtree_size(u, -1)
n = sizes[u]
u = find_centroid(u, -1)
lookup[u] = True
max_d = 0
for v in adj[u]:
if lookup[v]:
continue
cnt = []
count(v, u, 0+1)
prefix[v].append(0)
for d in xrange(len(cnt)):
prefix[v].append(prefix[v][-1]+cnt[d])
max_d = max(max_d, len(cnt))
total = [1]*(max_d+1)
for v in adj[u]:
if lookup[v]:
continue
for d in xrange(len(total)):
total[d] += prefix[v][min(d, len(prefix[v])-1)]
result[u] += total[min(k, len(total)-1)]
for v in adj[u]:
if lookup[v]:
continue
curr, prefix[v] = prefix[v], []
update(v, u, 0+1)
for v in adj[u]:
if lookup[v]:
continue
dfs(v)
result = [0]*len(adj)
sizes = [0]*len(adj)
lookup = [False]*len(adj)
prefix = [[] for _ in xrange(len(adj))]
if k >= 0:
dfs(0)
return result
def find_adj(edges):
adj = [[] for _ in xrange(len(edges)+1)]
for u, v in edges:
adj[u].append(v)
adj[v].append(u)
return adj
adj2 = find_adj(edges2)
mx = max(centroid_decomposition(adj2, k-1))
adj1 = find_adj(edges1)
return [mx+x for x in centroid_decomposition(adj1, k)]
# Time: O((n + m) * k)
# Space: O((n + m) * k)
# dfs, tree dp
class Solution2(object):
def maxTargetNodes(self, edges1, edges2, k):
"""
:type edges1: List[List[int]]
:type edges2: List[List[int]]
:type k: int
:rtype: List[int]
"""
def tree_dp(adj, k):
def dfs1(u, p):
for v in adj[u]:
if v == p:
continue
dfs1(v, u)
dp[u][0] += 1
for v in adj[u]:
if v == p:
continue
for d in xrange(k):
dp[u][d+1] += dp[v][d]
def dfs2(u, p, curr):
def update(v, u, curr):
new_curr = [0]*len(curr)
for d in xrange(len(curr)-1):
new_curr[d+1] = curr[d]+(dp[u][d]-(dp[v][d-1] if d-1 >= 0 else 0))
return new_curr
for v in adj[u]:
if v == p:
continue
dfs2(v, u, update(v, u, curr))
result[u] = sum(dp[u][i]+curr[i] for i in xrange(len(curr)))
result = [0]*len(adj)
k = min(k, len(adj)-1)
if k == -1:
return result
dp = [[0]*(k+1) for _ in xrange(len(adj))]
dfs1(0, -1)
dfs2(0, -1, [0]*(k+1))
return result
def find_adj(edges):
adj = [[] for _ in xrange(len(edges)+1)]
for u, v in edges:
adj[u].append(v)
adj[v].append(u)
return adj
adj2 = find_adj(edges2)
mx = max(tree_dp(adj2, k-1))
adj1 = find_adj(edges1)
return [mx+x for x in tree_dp(adj1, k)]
# Time: O(n^2 + m^2)
# Space: O(n + m)
# brute force, bfs
class Solution3(object):
def maxTargetNodes(self, edges1, edges2, k):
"""
:type edges1: List[List[int]]
:type edges2: List[List[int]]
:type k: int
:rtype: List[int]
"""
def bfs(u, adj, k):
result = 0
q = [(u, -1)]
while q:
if k == -1:
break
k -= 1
new_q = []
result += len(q)
for u, p in q:
for v in adj[u]:
if v == p:
continue
new_q.append((v, u))
q = new_q
return result
def find_adj(edges):
adj = [[] for _ in xrange(len(edges)+1)]
for u, v in edges:
adj[u].append(v)
adj[v].append(u)
return adj
adj2 = find_adj(edges2)
mx = max(bfs(u, adj2, k-1) for u in xrange(len(adj2)))
adj1 = find_adj(edges1)
return [mx+bfs(u, adj1, k) for u in xrange(len(adj1))]
Solution from kamyu104/LeetCode-Solutions · MIT
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