1854. Maximum Population Year
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Difficulty: easy Acceptance: 63% Topics: Array, Counting, Prefix Sum
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Reference solution (spoiler · python)
# Time: O(n)
# Space: O(1)
class Solution(object):
def maximumPopulation(self, logs):
"""
:type logs: List[List[int]]
:rtype: int
"""
MIN_YEAR, MAX_YEAR = 1950, 2050
years = [0]*(MAX_YEAR-MIN_YEAR+1)
for s, e in logs:
years[s-MIN_YEAR] += 1
years[e-MIN_YEAR] -= 1
result = 0
for i in xrange(len(years)):
if i:
years[i] += years[i-1]
if years[i] > years[result]:
result = i
return result+MIN_YEAR
Solution from kamyu104/LeetCode-Solutions · MIT
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