3115. Maximum Prime Difference
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 57% Topics: Array, Math, Number Theory
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Reference solution (spoiler · python)
# Time: O(r + n), r = max(nums)
# Space: O(r)
# linear sieve of eratosthenes, number theory
def linear_sieve_of_eratosthenes(n): # Time: O(n), Space: O(n)
primes = []
spf = [-1]*(n+1) # the smallest prime factor
for i in xrange(2, n+1):
if spf[i] == -1:
spf[i] = i
primes.append(i)
for p in primes:
if i*p > n or p > spf[i]:
break
spf[i*p] = p
return spf
MAX_N = 100
SPF = linear_sieve_of_eratosthenes(MAX_N)
class Solution(object):
def maximumPrimeDifference(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
left = next(i for i in xrange(len(nums)) if SPF[nums[i]] == nums[i])
right = next(i for i in reversed(xrange(len(nums))) if SPF[nums[i]] == nums[i])
return right-left
Solution from kamyu104/LeetCode-Solutions · MIT