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LC-3115 Medium LeetCode

3115. Maximum Prime Difference

Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 57% Topics: Array, Math, Number Theory
View full problem on LeetCode
Reference solution (spoiler · python)
# Time:  O(r + n), r = max(nums)
# Space: O(r)

# linear sieve of eratosthenes, number theory
def linear_sieve_of_eratosthenes(n):  # Time: O(n), Space: O(n)
    primes = []
    spf = [-1]*(n+1)  # the smallest prime factor
    for i in xrange(2, n+1):
        if spf[i] == -1:
            spf[i] = i
            primes.append(i)
        for p in primes:
            if i*p > n or p > spf[i]:
                break
            spf[i*p] = p
    return spf


MAX_N = 100
SPF = linear_sieve_of_eratosthenes(MAX_N)
class Solution(object):
    def maximumPrimeDifference(self, nums):
        """
        :type nums: List[int]
        :rtype: int
        """
        left = next(i for i in xrange(len(nums)) if SPF[nums[i]] == nums[i])
        right = next(i for i in reversed(xrange(len(nums))) if SPF[nums[i]] == nums[i])
        return right-left

Solution from kamyu104/LeetCode-Solutions · MIT