1829. Maximum XOR for Each Query
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Difficulty: medium Acceptance: 85% Topics: Array, Bit Manipulation, Prefix Sum
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Reference solution (spoiler · python)
# Time: O(n)
# Space: O(1)
class Solution(object):
def getMaximumXor(self, nums, maximumBit):
"""
:type nums: List[int]
:type maximumBit: int
:rtype: List[int]
"""
result = [0]*len(nums)
mask = 2**maximumBit-1
for i in xrange(len(nums)):
mask ^= nums[i]
result[-1-i] = mask
return result
Solution from kamyu104/LeetCode-Solutions · MIT
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