2939. Maximum Xor Product
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Difficulty: medium Acceptance: 27% Topics: Math, Greedy, Bit Manipulation
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Reference solution (spoiler · python)
# Time: O(n)
# Space: O(1)
# greedy
class Solution(object):
def maximumXorProduct(self, a, b, n):
"""
:type a: int
:type b: int
:type n: int
:rtype: int
"""
MOD = 10**9+7
for i in reversed(xrange(n)):
base = 1<<i
if min(a, b)&base == 0:
a, b = a^base, b^base
return (a%MOD)*(b%MOD)%MOD
Solution from kamyu104/LeetCode-Solutions · MIT
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