1675. Minimize Deviation in Array
Read the full problem statement on LeetCode.
Difficulty: hard Acceptance: 54% Topics: Array, Greedy, Heap (Priority Queue), Ordered Set
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O((n * log(max_num)) * logn)
# Space: O(n)
import heapq
class Solution(object):
def minimumDeviation(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
max_heap = [-num*2 if num%2 else -num for num in nums]
heapq.heapify(max_heap)
min_elem = -max(max_heap)
result = float("inf")
while len(max_heap) == len(nums):
num = -heapq.heappop(max_heap)
result = min(result, num-min_elem)
if not num%2:
min_elem = min(min_elem, num//2)
heapq.heappush(max_heap, -num//2)
return result
Solution from kamyu104/LeetCode-Solutions · MIT