433. Minimum Genetic Mutation
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 55% Topics: Hash Table, String, Breadth-First Search
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(n * b), n is the length of gene string, b is size of bank
# Space: O(b)
from collections import deque
class Solution(object):
def minMutation(self, start, end, bank):
"""
:type start: str
:type end: str
:type bank: List[str]
:rtype: int
"""
lookup = {}
for b in bank:
lookup[b] = False
q = deque([(start, 0)])
while q:
cur, level = q.popleft()
if cur == end:
return level
for i in xrange(len(cur)):
for c in ['A', 'T', 'C', 'G']:
if cur[i] == c:
continue
next_str = cur[:i] + c + cur[i+1:]
if next_str in lookup and lookup[next_str] == False:
q.append((next_str, level+1))
lookup[next_str] = True
return -1
Solution from kamyu104/LeetCode-Solutions · MIT
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