3292. Minimum Number of Valid Strings to Form Target II
Array String Binary Search Dynamic Programming Segment Tree Rolling Hash String Matching Hash Function
Read the full problem statement on LeetCode.
Difficulty: hard Acceptance: 18% Topics: Array, String, Binary Search, Dynamic Programming, Segment Tree, Rolling Hash, String Matching, Hash Function
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(n + w * l)
# Space: O(n + w * l)
# rolling hash, hash table, two pointers, sliding window, dp
class Solution(object):
def minValidStrings(self, words, target):
"""
:type words: List[str]
:type target: str
:rtype: int
"""
MOD, P = 10**9+7, 131
power = [1]
for _ in xrange(len(target)):
power.append(power[-1]*P%MOD)
lookup = set()
for w in words:
h = 0
for x in w:
h = (h*P+(ord(x)-ord('a')+1))%MOD
lookup.add(h)
dp = [0]*(len(target)+1)
left = h = 0
for right in xrange(len(target)):
h = (h*P+(ord(target[right])-ord('a')+1))%MOD
while right-left+1 >= 1 and h not in lookup:
h = (h-(ord(target[left])-ord('a')+1)*power[(right-left+1)-1])%MOD
left += 1
if right-left+1 == 0:
return -1
dp[right+1] = dp[(right-(right-left+1))+1]+1
return dp[-1]
# Time: O(n + w * l)
# Space: O(n + t), t is the total size of ac automata trie
import collections
class AhoNode(object):
def __init__(self):
self.children = collections.defaultdict(AhoNode)
# self.indices = []
self.suffix = None
# self.output = None
self.length = 0 # added
class AhoTrie(object):
def step(self, letter):
while self.__node and letter not in self.__node.children:
self.__node = self.__node.suffix
self.__node = self.__node.children[letter] if self.__node else self.__root
return self.__get_ac_node_outputs(self.__node)
def __init__(self, patterns):
self.__root = self.__create_ac_trie(patterns)
self.__node = self.__create_ac_suffix_and_output_links(self.__root)
def __create_ac_trie(self, patterns): # Time: O(n), Space: O(t)
root = AhoNode()
for i, pattern in enumerate(patterns):
node = root
for l, c in enumerate(pattern, 1): # modified
node = node.children[c]
node.length = l # added
# node.indices.append(i)
return root
def __create_ac_suffix_and_output_links(self, root): # Time: O(n), Space: O(t)
queue = collections.deque()
for node in root.children.itervalues():
queue.append(node)
node.suffix = root
while queue:
node = queue.popleft()
for c, child in node.children.iteritems():
queue.append(child)
suffix = node.suffix
while suffix and c not in suffix.children:
suffix = suffix.suffix
child.suffix = suffix.children[c] if suffix else root
# child.output = child.suffix if child.suffix.indices else child.suffix.output
return root
def __get_ac_node_outputs(self, node): # Time: O(z)
return node.length # modified
# result = []
# for i in node.indices:
# result.append(i)
# output = node.output
# while output:
# for i in output.indices:
# result.append(i)
# output = output.output
# return result
# ac automata trie
class Solution2(object):
def minValidStrings(self, words, target):
"""
:type words: List[str]
:type target: str
:rtype: int
"""
trie = AhoTrie(words)
dp = [0]*(len(target)+1)
for i in xrange(len(target)):
l = trie.step(target[i])
if not l:
return -1
dp[i+1] = dp[(i-l)+1]+1
return dp[-1]
# Time: O(w * (l + n))
# Space: O(l + n)
# kmp, dp
class Solution3(object):
def minValidStrings(self, words, target):
"""
:type words: List[str]
:type target: str
:rtype: int
"""
def getPrefix(pattern):
prefix = [-1]*len(pattern)
j = -1
for i in xrange(1, len(pattern)):
while j+1 > 0 and pattern[j+1] != pattern[i]:
j = prefix[j]
if pattern[j+1] == pattern[i]:
j += 1
prefix[i] = j
return prefix
def KMP(text, pattern, callback):
prefix = getPrefix(pattern)
j = -1
for i in xrange(len(text)):
while j+1 > 0 and pattern[j+1] != text[i]:
j = prefix[j]
if pattern[j+1] == text[i]:
j += 1
callback(i, j)
if j+1 == len(pattern):
j = prefix[j]
def update(i, j):
lookup[i] = max(lookup[i], j+1)
lookup = [0]*len(target)
for w in words:
KMP(target, w, update)
dp = [0]*(len(target)+1)
for i in xrange(len(target)):
if not lookup[i]:
return -1
dp[i+1] = dp[(i-lookup[i])+1]+1
return dp[-1]
Solution from kamyu104/LeetCode-Solutions · MIT