3402. Minimum Operations to Make Columns Strictly Increasing
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Difficulty: easy Acceptance: 72% Topics: Array, Greedy, Matrix
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Reference solution (spoiler · python)
# Time: O(m * n)
# Space: O(1)
# greedy
class Solution(object):
def minimumOperations(self, grid):
"""
:type grid: List[List[int]]
:rtype: int
"""
result = 0
for i in xrange(len(grid)-1):
for j in xrange(len(grid[0])):
if grid[i][j]+1 <= grid[i+1][j]:
continue
result += (grid[i][j]+1)-grid[i+1][j]
grid[i+1][j] = grid[i][j]+1
return result
Solution from kamyu104/LeetCode-Solutions · MIT
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