2187. Minimum Time to Complete Trips
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Difficulty: medium Acceptance: 39% Topics: Array, Binary Search
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Reference solution (spoiler · python)
# Time: O(nlogr)
# Space: O(1)
# binary search
class Solution(object):
def minimumTime(self, time, totalTrips):
"""
:type time: List[int]
:type totalTrips: int
:rtype: int
"""
def check(time, totalTrips, x):
return sum(x//t for t in time) >= totalTrips
left, right = 1, max(time)*totalTrips
while left <= right:
mid = left + (right-left)//2
if check(time, totalTrips, mid):
right = mid-1
else:
left = mid+1
return left
Solution from kamyu104/LeetCode-Solutions · MIT