2699. Modify Graph Edge Weights
Read the full problem statement on LeetCode.
Difficulty: hard Acceptance: 56% Topics: Graph, Heap (Priority Queue), Shortest Path
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Reference solution (spoiler · python)
# Time: O((|E| + |V|) * log|V|) = O(|E| * log|V|) by using binary heap,
# if we can further to use Fibonacci heap, it would be O(|E| + |V| * log|V|)
# Space: O(|E| + |V|) = O(|E|)
import heapq
# dijkstra's algorithm
class Solution(object):
def modifiedGraphEdges(self, n, edges, source, destination, target):
"""
:type n: int
:type edges: List[List[int]]
:type source: int
:type destination: int
:type target: int
:rtype: List[List[int]]
"""
def dijkstra(start, x):
best = [target+1]*len(adj)
best[start] = 0
min_heap = [(0, start)]
while min_heap:
curr, u = heapq.heappop(min_heap)
if curr > best[u]:
continue
for v, w in adj[u]:
if w == -1:
w = x
if curr+w >= best[v]:
continue
best[v] = curr+w
heapq.heappush(min_heap, (best[v], v))
return best
adj = [[] for _ in xrange(n)]
for u, v, w in edges:
adj[u].append((v, w))
adj[v].append((u, w))
left = dijkstra(source, 1)
if not (left[destination] <= target):
return []
right= dijkstra(destination, target+1)
if not (right[source] >= target):
return []
for e in edges:
if e[2] == -1:
e[2] = max(target-left[e[0]]-right[e[1]], target-left[e[1]]-right[e[0]], 1)
return edges
Solution from kamyu104/LeetCode-Solutions · MIT