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LC-0556 Medium LeetCode

556. Next Greater Element III

Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 35% Topics: Math, Two Pointers, String
View full problem on LeetCode
Reference solution (spoiler · python)
# Time:  O(logn) = O(1)
# Space: O(logn) = O(1)


class Solution(object):
    def nextGreaterElement(self, n):
        """
        :type n: int
        :rtype: int
        """
        digits = map(int, list(str(n)))
        k, l = -1, 0
        for i in xrange(len(digits) - 1):
            if digits[i] < digits[i + 1]:
                k = i

        if k == -1:
            digits.reverse()
            return -1

        for i in xrange(k + 1, len(digits)):
            if digits[i] > digits[k]:
                l = i

        digits[k], digits[l] = digits[l], digits[k]
        digits[k + 1:] = digits[:k:-1]
        result = int("".join(map(str, digits)))
        return -1 if result >= 0x7FFFFFFF else result

Solution from kamyu104/LeetCode-Solutions · MIT