323. Number of Connected Components in an Undirected Graph
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 64% Topics: Depth-First Search, Breadth-First Search, Union Find, Graph
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(nlog*n) ~= O(n), n is the length of the positions
# Space: O(n)
class UnionFind(object):
def __init__(self, n):
self.set = range(n)
self.count = n
def find_set(self, x):
if self.set[x] != x:
self.set[x] = self.find_set(self.set[x]) # path compression.
return self.set[x]
def union_set(self, x, y):
x_root, y_root = map(self.find_set, (x, y))
if x_root != y_root:
self.set[min(x_root, y_root)] = max(x_root, y_root)
self.count -= 1
class Solution(object):
def countComponents(self, n, edges):
"""
:type n: int
:type edges: List[List[int]]
:rtype: int
"""
union_find = UnionFind(n)
for i, j in edges:
union_find.union_set(i, j)
return union_find.count
Solution from kamyu104/LeetCode-Solutions · MIT