1805. Number of Different Integers in a String

# Time:  O(n)
# Space: O(n)

class Solution(object):
    def numDifferentIntegers(self, word):
        """
        :type word: str
        :rtype: int
        """
        result, num = set(), None
        for i in xrange(len(word)+1):
            c = word[i] if i < len(word) else ' '
            if c.isdigit():
                num = 10*num+int(c) if num is not None else int(c)
            elif num is not None:
                result.add(num)
                num = None
        return len(result)

Solution from kamyu104/LeetCode-Solutions · MIT