752. Open the Lock
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 61% Topics: Array, Hash Table, String, Breadth-First Search
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(k * n^k + d), n is the number of alphabets,
# k is the length of target,
# d is the size of deadends
# Space: O(k * n^k + d)
class Solution(object):
def openLock(self, deadends, target):
"""
:type deadends: List[str]
:type target: str
:rtype: int
"""
dead = set(deadends)
q = ["0000"]
lookup = {"0000"}
depth = 0
while q:
next_q = []
for node in q:
if node == target: return depth
if node in dead: continue
for i in xrange(4):
n = int(node[i])
for d in (-1, 1):
nn = (n+d) % 10
neighbor = node[:i] + str(nn) + node[i+1:]
if neighbor not in lookup:
lookup.add(neighbor)
next_q.append(neighbor)
q = next_q
depth += 1
return -1
Solution from kamyu104/LeetCode-Solutions · MIT
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