3429. Paint House IV
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 43% Topics: Array, Dynamic Programming
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(n * l^4)
# Space: O(l^2)
# dp
class Solution(object):
def minCost(self, n, cost):
"""
:type n: int
:type cost: List[List[int]]
:rtype: int
"""
l = len(cost[0])
dp = [[0]*l for i in xrange(l)]
for k in xrange(n//2):
new_dp = [[float("inf")]*l for i in xrange(l)]
for i in xrange(l):
for j in xrange(l):
if j == i:
continue
for ni in xrange(l):
if ni == i:
continue
for nj in xrange(l):
if nj == j or ni == nj:
continue
new_dp[ni][nj] = min(new_dp[ni][nj], dp[i][j]+cost[k][ni]+cost[~k][nj])
dp = new_dp
return min(dp[i][j] for i in xrange(l) for j in xrange(l) if i != j)
Solution from kamyu104/LeetCode-Solutions · MIT
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