86. Partition List
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 59% Topics: Linked List, Two Pointers
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(n)
# Space: O(1)
class ListNode(object):
def __init__(self, x):
self.val = x
self.next = None
def __repr__(self):
if self:
return "{} -> {}".format(self.val, repr(self.next))
class Solution(object):
# @param head, a ListNode
# @param x, an integer
# @return a ListNode
def partition(self, head, x):
dummySmaller, dummyGreater = ListNode(-1), ListNode(-1)
smaller, greater = dummySmaller, dummyGreater
while head:
if head.val < x:
smaller.next = head
smaller = smaller.next
else:
greater.next = head
greater = greater.next
head = head.next
smaller.next = dummyGreater.next
greater.next = None
return dummySmaller.next
Solution from kamyu104/LeetCode-Solutions · MIT
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