119. Pascal's Triangle II
Read the full problem statement on LeetCode.
Difficulty: easy Acceptance: 66% Topics: Array, Dynamic Programming
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(n^2)
# Space: O(1)
class Solution(object):
# @return a list of integers
def getRow(self, rowIndex):
result = [0] * (rowIndex + 1)
for i in xrange(rowIndex + 1):
old = result[0] = 1
for j in xrange(1, i + 1):
old, result[j] = result[j], old + result[j]
return result
def getRow2(self, rowIndex):
"""
:type rowIndex: int
:rtype: List[int]
"""
row = [1]
for _ in range(rowIndex):
row = [x + y for x, y in zip([0] + row, row + [0])]
return row
def getRow3(self, rowIndex):
"""
:type rowIndex: int
:rtype: List[int]
"""
if rowIndex == 0: return [1]
res = [1, 1]
def add(nums):
res = nums[:1]
for i, j in enumerate(nums):
if i < len(nums) - 1:
res += [nums[i] + nums[i + 1]]
res += nums[:1]
return res
while res[1] < rowIndex:
res = add(res)
return res
# Time: O(n^2)
# Space: O(n)
class Solution2(object):
# @return a list of integers
def getRow(self, rowIndex):
result = [1]
for i in range(1, rowIndex + 1):
result = [1] + [result[j - 1] + result[j] for j in xrange(1, i)] + [1]
return result
Solution from kamyu104/LeetCode-Solutions · MIT
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