406. Queue Reconstruction by Height
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 74% Topics: Array, Binary Indexed Tree, Segment Tree, Sorting
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Reference solution (spoiler · python)
# Time: O(n * sqrt(n))
# Space: O(n)
class Solution(object):
def reconstructQueue(self, people):
"""
:type people: List[List[int]]
:rtype: List[List[int]]
"""
people.sort(key=lambda h_k: (-h_k[0], h_k[1]))
blocks = [[]]
for p in people:
index = p[1]
for i, block in enumerate(blocks):
if index <= len(block):
break
index -= len(block)
block.insert(index, p)
if len(block) * len(block) > len(people):
blocks.insert(i+1, block[len(block)/2:])
del block[len(block)/2:]
return [p for block in blocks for p in block]
# Time: O(n^2)
# Space: O(n)
class Solution2(object):
def reconstructQueue(self, people):
"""
:type people: List[List[int]]
:rtype: List[List[int]]
"""
people.sort(key=lambda h_k1: (-h_k1[0], h_k1[1]))
result = []
for p in people:
result.insert(p[1], p)
return result
Solution from kamyu104/LeetCode-Solutions · MIT
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