519. Random Flip Matrix
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 43% Topics: Hash Table, Math, Reservoir Sampling, Randomized
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: ctor: O(1)
# flip: O(1)
# reset: O(min(f, r * c))
# Space: O(min(f, r * c))
import random
class Solution(object):
def __init__(self, n_rows, n_cols):
"""
:type n_rows: int
:type n_cols: int
"""
self.__n_rows = n_rows
self.__n_cols = n_cols
self.__n = n_rows*n_cols
self.__lookup = {}
def flip(self):
"""
:rtype: List[int]
"""
self.__n -= 1
target = random.randint(0, self.__n)
x = self.__lookup.get(target, target)
self.__lookup[target] = self.__lookup.get(self.__n, self.__n)
return divmod(x, self.__n_cols)
def reset(self):
"""
:rtype: void
"""
self.__n = self.__n_rows*self.__n_cols
self.__lookup = {}
Solution from kamyu104/LeetCode-Solutions · MIT