1338. Reduce Array Size to The Half
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 69% Topics: Array, Hash Table, Greedy, Sorting, Heap (Priority Queue)
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Reference solution (spoiler · python)
# Time: O(n)
# Space: O(n)
import collections
class Solution(object):
def minSetSize(self, arr):
"""
:type arr: List[int]
:rtype: int
"""
counting_sort = [0]*len(arr)
count = collections.Counter(arr)
for c in count.itervalues():
counting_sort[c-1] += 1
result, total = 0, 0
for c in reversed(xrange(len(arr))):
if not counting_sort[c]:
continue
count = min(counting_sort[c],
((len(arr)+1)//2 - total - 1)//(c+1) + 1)
result += count
total += count*(c+1)
if total >= (len(arr)+1)//2:
break
return result
Solution from kamyu104/LeetCode-Solutions · MIT