2259. Remove Digit From Number to Maximize Result
Read the full problem statement on LeetCode.
Difficulty: easy Acceptance: 47% Topics: String, Greedy, Enumeration
View full problem on LeetCode Reading material
Reference solution (spoiler · python)
# Time: O(n)
# Space: O(1)
# greedy
class Solution(object):
def removeDigit(self, number, digit):
"""
:type number: str
:type digit: str
:rtype: str
"""
i = next((i for i in xrange(len(number)-1) if digit == number[i] < number[i+1]), len(number)-1)
if i+1 == len(number):
i = next((i for i in reversed(xrange(len(number))) if digit == number[i]))
return number[:i]+number[i+1:]
Solution from kamyu104/LeetCode-Solutions · MIT