LC-0143 Medium LeetCode

143. Reorder List

Linked List Two Pointers Stack Recursion

Read the full problem statement on LeetCode.

Difficulty: medium Acceptance: 62% Topics: Linked List, Two Pointers, Stack, Recursion

Reading material

Linked Lists 14 min Two Pointers 9 min Stacks & Queues 11 min

Reference solution (spoiler · python)

# Time:  O(n)
# Space: O(1)

class ListNode(object):
    def __init__(self, x):
        self.val = x
        self.next = None

    def __repr__(self):
        if self:
            return "{} -> {}".format(self.val, repr(self.next))

class Solution(object):
    # @param head, a ListNode
    # @return nothing
    def reorderList(self, head):
        if head == None or head.next == None:
            return head

        fast, slow, prev = head, head, None
        while fast != None and fast.next != None:
            fast, slow, prev = fast.next.next, slow.next, slow
        current, prev.next, prev = slow, None, None

        while current != None:
            current.next, prev, current = prev, current, current.next

        l1, l2 = head, prev
        dummy = ListNode(0)
        current = dummy

        while l1 != None and l2 != None:
            current.next, current, l1 = l1, l1, l1.next
            current.next, current, l2 = l2, l2, l2.next

        return dummy.next

Solution from kamyu104/LeetCode-Solutions · MIT