3081. Replace Question Marks in String to Minimize Its Value
Read the full problem statement on LeetCode.
Difficulty: medium Acceptance: 28% Topics: Hash Table, String, Greedy, Sorting, Heap (Priority Queue), Counting
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Reference solution (spoiler · python)
# Time: O(n + 26 * log(26))
# Space: O(26)
# greedy, counting sort, prefix sum
class Solution(object):
def minimizeStringValue(self, s):
"""
:type s: str
:rtype: str
"""
def counting_sort(cnt):
for i in xrange(len(cnt)):
for _ in xrange(cnt[i]):
yield i
def fill(cnt):
result = [0]*26
a = [(x, i) for i, x in enumerate(cnt)]
a.sort()
total = s.count('?')
curr = 0
for i in xrange(len(a)-1):
if curr+(a[i+1][0]-a[i][0])*(i+1) > total:
break
curr += (a[i+1][0]-a[i][0])*(i+1)
else:
i = len(a)-1
q, r = divmod(total-curr, i+1)
for j in xrange(i+1):
result[a[j][1]] = (a[i][0]-a[j][0])+q
cnt2 = [0]*26
for j in xrange(i+1):
cnt2[a[j][1]] += 1
it = counting_sort(cnt2)
for _ in xrange(r):
result[next(it)] += 1
return result
cnt = [0]*26
for x in s:
if x == '?':
continue
cnt[ord(x)-ord('a')] += 1
it = counting_sort(fill(cnt))
result = list(s)
for i in xrange(len(result)):
if result[i] != '?':
continue
result[i] = chr(ord('a')+next(it))
return "".join(result)
# Time: O(n + n * log(26))
# Space: O(26)
import heapq
# greedy, counting sort, heap
class Solution2(object):
def minimizeStringValue(self, s):
"""
:type s: str
:rtype: str
"""
def counting_sort(cnt):
for i in xrange(len(cnt)):
for _ in xrange(cnt[i]):
yield i
cnt = [0]*26
for x in s:
if x == '?':
continue
cnt[ord(x)-ord('a')] += 1
min_heap = [(x, i) for i, x in enumerate(cnt)]
heapq.heapify(min_heap)
cnt2 = [0]*26
for _ in xrange(s.count('?')):
c, i = heapq.heappop(min_heap)
heapq.heappush(min_heap, (c+1, i))
cnt2[i] += 1
it = counting_sort(cnt2)
result = list(s)
for i in xrange(len(result)):
if result[i] != '?':
continue
result[i] = chr(ord('a')+next(it))
return "".join(result)
# Time: O(n + n * 26)
# Space: O(26)
# greedy, counting sort
class Solution3(object):
def minimizeStringValue(self, s):
"""
:type s: str
:rtype: str
"""
def counting_sort(cnt):
for i in xrange(len(cnt)):
for _ in xrange(cnt[i]):
yield i
cnt = [0]*26
for x in s:
if x == '?':
continue
cnt[ord(x)-ord('a')] += 1
cnt2 = [0]*26
for _ in xrange(s.count('?')):
i = min(xrange(len(cnt)), key=lambda x: cnt[x]+cnt2[x])
cnt2[i] += 1
it = counting_sort(cnt2)
result = list(s)
for i in xrange(len(result)):
if result[i] != '?':
continue
result[i] = chr(ord('a')+next(it))
return "".join(result)
Solution from kamyu104/LeetCode-Solutions · MIT
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